Question:
The area of a rectangle of sides 14 cm and 22 cm is equal to the area of a circle. If the diameter of the circle is 50% less than the side of a square then find the area of the square?
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Description:
Area of the circle = πr2 = area of the rectangle = l × b = 14 × 22 = 22 × r2 , 7 by solving r = 7√2 cm,the diameter of the circle = 2 × 7√2 cm = 14√2 cm = 50% less than the sides of a square Sides of the square = 14√2 cm × 100 = 28√2 cm, 50 Area of the square = sides2 = (28√2 cm)2 = 1568 cm2
This question was added in the model test of AD Preli Test -12
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click hereCoaching/Teacher: Abdul Wadud
Syllabus: Bank Preli Syllabus